PhysicsJME

Thermal Properties: Expansion, Calorimetry & Heat Transfer

Apply concepts from Thermal Properties: Expansion, Calorimetry & Heat Transfer to problem-solving. Focus on numerical practice, shortcuts, and real-world applications.

2%45 minPhase 3 · APPLICATIONMCQ + Numerical

Concept Core

Thermal Expansion

When a body is heated, its dimensions increase due to increased molecular vibrations. Three types of expansion:

Linear Expansion: ΔL=L0αΔTL=L0(1+αΔT)\Delta L = L_0 \alpha \Delta T \quad \Rightarrow \quad L = L_0(1 + \alpha \Delta T)

  • α\alpha: coefficient of linear expansion (K1^{-1})
  • Typical values: steel 12×106\approx 12 \times 10^{-6} K1^{-1}, aluminium 23×106\approx 23 \times 10^{-6} K1^{-1}

Area Expansion: ΔA=A0βΔTA=A0(1+βΔT)\Delta A = A_0 \beta \Delta T \quad \Rightarrow \quad A = A_0(1 + \beta \Delta T)

  • β\beta: coefficient of area expansion; β=2α\beta = 2\alpha

Volume Expansion: ΔV=V0γΔTV=V0(1+γΔT)\Delta V = V_0 \gamma \Delta T \quad \Rightarrow \quad V = V_0(1 + \gamma \Delta T)

  • γ\gamma: coefficient of volume expansion; γ=3α\gamma = 3\alpha

Relation: α:β:γ=1:2:3\alpha : \beta : \gamma = 1 : 2 : 3

Linear Expansion of a Bar

Expansion of Holes and Cavities

A hole or cavity in a solid expands exactly as if it were filled with the same material. A metal ring heated gets a larger inner diameter, not smaller.

Thermal Stress

When expansion is constrained: σ=YαΔT\sigma = Y\alpha\Delta T, F=YAαΔTF = YA\alpha\Delta T (covered in JME-08 but relevant here).

Anomalous Expansion of Water

Water has maximum density at 4 degrees C. Between 0 degrees C and 4 degrees C, water contracts on heating (anomalous). Above 4 degrees C, it expands normally. This is crucial for aquatic life — lakes freeze from the top while the bottom stays at 4 degrees C.

Calorimetry

Heat capacity: C=ΔQΔTC = \frac{\Delta Q}{\Delta T} (J K1^{-1})

Specific heat capacity: c=ΔQmΔTc = \frac{\Delta Q}{m \Delta T} (J kg1^{-1} K1^{-1})

Molar heat capacity: Cm=ΔQnΔTC_m = \frac{\Delta Q}{n \Delta T} (J mol1^{-1} K1^{-1})

Principle of Calorimetry (conservation of energy): Heat lost by hot body=Heat gained by cold body\text{Heat lost by hot body} = \text{Heat gained by cold body} m1c1(T1Tf)=m2c2(TfT2)m_1 c_1 (T_1 - T_f) = m_2 c_2 (T_f - T_2)

Latent Heat

Latent heat of fusion: LfL_f — heat required to change unit mass from solid to liquid at constant temperature. Q=mLfQ = mL_f

  • Water: Lf=3.34×105L_f = 3.34 \times 10^5 J kg1^{-1} = 80 cal g1^{-1}

Latent heat of vaporization: LvL_v — heat required to change unit mass from liquid to gas at constant temperature. Q=mLvQ = mL_v

  • Water: Lv=2.26×106L_v = 2.26 \times 10^6 J kg1^{-1} = 540 cal g1^{-1}

Heat Transfer Mechanisms

1. Conduction: dQdt=kA(T1T2)L\frac{dQ}{dt} = \frac{kA(T_1 - T_2)}{L}

  • kk: thermal conductivity (W m1^{-1} K1^{-1})
  • AA: cross-sectional area
  • LL: length of conductor
  • Dimensional formula of kk: [M L T3^{-3} K1^{-1}]

Thermal resistance: R=L/(kA)R = L/(kA) (analogous to electrical resistance)

For slabs in series: Rtotal=R1+R2+...R_{\text{total}} = R_1 + R_2 + ... For slabs in parallel: 1/Rtotal=1/R1+1/R2+...1/R_{\text{total}} = 1/R_1 + 1/R_2 + ...

Heat conduction through composite wall — two slabs in series Conduction Through Composite Wall (Series)

2. Convection: Heat transfer by bulk movement of fluid. Natural convection (density-driven) and forced convection (fan/pump driven). Not easily quantified by simple formulas at the JEE level.

3. Radiation: Stefan-Boltzmann Law: E=σT4(power per unit area for a blackbody)E = \sigma T^4 \quad \text{(power per unit area for a blackbody)} P=σAT4(total power radiated)P = \sigma A T^4 \quad \text{(total power radiated)}

  • σ=5.67×108\sigma = 5.67 \times 10^{-8} W m2^{-2} K4^{-4} (Stefan-Boltzmann constant)

For a non-blackbody: P=eσAT4P = e\sigma A T^4 (where ee is emissivity, 0e10 \leq e \leq 1)

Newton's Law of Cooling (for small temperature excess): dTdt=bK(TTs)\frac{dT}{dt} = -bK(T - T_s) where TsT_s is surrounding temperature. Approximately: T1T2t=k(T1+T22Ts)\frac{T_1 - T_2}{t} = k\left(\frac{T_1 + T_2}{2} - T_s\right)

Wien's Displacement Law: λmaxT=b=2.898×103 m K\lambda_{\max} T = b = 2.898 \times 10^{-3} \text{ m K} Higher temperature shifts peak wavelength to shorter (bluer) wavelengths.


Key Testable Concept

---

Study Materials

Available in the NoteTube app — start studying for free.

100 Flashcards

SM-2 spaced repetition flashcards with hints and explanations

100 Quiz Questions

Foundation and PYQ-style questions with AI feedback

15 Study Notes

Structured notes across 10 scientifically grounded formats

10 Summaries

Progressive summaries from comprehensive guides to cheat sheets

Continue studying in NoteTube

Frequently Asked Questions

Common questions about studying Thermal Properties: Expansion, Calorimetry & Heat Transfer for JEE Main 2027.

Thermal Properties: Expansion, Calorimetry & Heat Transfer — JEE Main 2027 Physics | NoteTube