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Simple Harmonic Motion

Apply concepts from Simple Harmonic Motion to problem-solving. Focus on numerical practice, shortcuts, and real-world applications.

3.3%50 minPhase 2 · APPLICATIONMCQ + Numerical

Concept Core

SHM as projection of uniform circular motion — a particle on a reference circle projects onto the y-axis to trace sinusoidal displacement

Simple Harmonic Motion (SHM) is the most fundamental oscillatory motion in physics.
A particle executes SHM when the restoring force is directly proportional to displacement from the mean position and directed towards it: F=kxF = -kx, where kk is the force constant.
This gives acceleration a=ω2xa = -\omega^2 x, where ω=k/m\omega = \sqrt{k/m} is the angular frequency.

The general equation of SHM is x(t)=Asin(ωt+ϕ)x(t) = A\sin(\omega t + \phi) or equivalently x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t + \phi'), where AA is the amplitude, ω\omega is the angular frequency, and ϕ\phi is the initial phase.
The velocity v=Aωcos(ωt+ϕ)=ωA2x2v = A\omega\cos(\omega t + \phi) = \omega\sqrt{A^2 - x^2} and acceleration a=Aω2sin(ωt+ϕ)=ω2xa = -A\omega^2\sin(\omega t + \phi) = -\omega^2 x.

The time period T=2π/ω=2πm/kT = 2\pi/\omega = 2\pi\sqrt{m/k} and frequency f=1/T=ω/(2π)f = 1/T = \omega/(2\pi).
For a simple pendulum of length ll: T=2πl/gT = 2\pi\sqrt{l/g} (valid for small angles θ<15°\theta < 15°).
For a spring-mass system: T=2πm/kT = 2\pi\sqrt{m/k}.

Spring Combinations:

  • Series: 1/keff=1/k1+1/k21/k_{\text{eff}} = 1/k_1 + 1/k_2, so keff=k1k2/(k1+k2)k_{\text{eff}} = k_1k_2/(k_1+k_2). Time period increases.
  • Parallel: keff=k1+k2k_{\text{eff}} = k_1 + k_2. Time period decreases.
  • A spring cut into ratio m:nm:n gives spring constants in inverse ratio: k1=k(m+n)/mk_1 = k(m+n)/m and k2=k(m+n)/nk_2 = k(m+n)/n.
Spring-mass system at three key positions — extreme left, mean (equilibrium), and extreme right

Energy in SHM:

  • Kinetic energy: KE=12mω2(A2x2)KE = \frac{1}{2}m\omega^2(A^2 - x^2)
  • Potential energy: PE=12mω2x2=12kx2PE = \frac{1}{2}m\omega^2 x^2 = \frac{1}{2}kx^2
  • Total energy: E=12mω2A2=12kA2E = \frac{1}{2}m\omega^2 A^2 = \frac{1}{2}kA^2 (constant, independent of position)
  • KE and PE oscillate with frequency 2ω2\omega (double the SHM frequency), and their average values are each E/2E/2.

Superposition of SHMs: When two SHMs of same frequency act along the same direction: x1=A1sin(ωt)x_1 = A_1\sin(\omega t) and x2=A2sin(ωt+ϕ)x_2 = A_2\sin(\omega t + \phi), the resultant is SHM with amplitude AR=A12+A22+2A1A2cosϕA_R = \sqrt{A_1^2 + A_2^2 + 2A_1A_2\cos\phi}.
When ϕ=0\phi = 0: AR=A1+A2A_R = A_1 + A_2 (constructive).
When ϕ=π\phi = \pi: AR=A1A2A_R = |A_1 - A_2| (destructive).

Damped Oscillations: In real systems, friction reduces amplitude exponentially: x=Aebt/(2m)sin(ωt+ϕ)x = Ae^{-bt/(2m)}\sin(\omega' t + \phi), where ω=ω02(b/2m)2\omega' = \sqrt{\omega_0^2 - (b/2m)^2} and bb is the damping coefficient. Energy decays as Eebt/mE \propto e^{-bt/m}.

Forced Oscillations and Resonance: When an external periodic force F=F0sin(ωdt)F = F_0\sin(\omega_d t) drives a damped oscillator, the steady-state amplitude peaks when ωdω0\omega_d \approx \omega_0 (resonance). At resonance, energy transfer from driver to oscillator is maximum. Sharpness of resonance depends inversely on damping.

The key problem-solving concept is recognizing that SHM is completely characterized by ω\omega, AA, and ϕ\phi — once these three are determined from initial conditions, every other quantity (velocity, acceleration, energy, time period) follows directly.

Key Testable Concept

The key problem-solving concept is recognizing that SHM is completely characterized by $\omega$, $A$, and $\phi$ — once these three are determined from initial conditions, every other quantity (velocity, acceleration, energy, time period) follows directly.

Comparison Tables

A) Spring Combinations

ConfigurationEffective kTime PeriodExample
Single springkk2πm/k2\pi\sqrt{m/k}Standard spring-mass
Series (k1,k2k_1, k_2)k1k2/(k1+k2)k_1k_2/(k_1+k_2)2πm(k1+k2)/(k1k2)2\pi\sqrt{m(k_1+k_2)/(k_1k_2)}Springs end-to-end
Parallel (k1,k2k_1, k_2)k1+k2k_1 + k_22πm/(k1+k2)2\pi\sqrt{m/(k_1+k_2)}Springs side-by-side
Spring cut 1:n1:n (piece 1)k(1+n)k(1+n)2πm/(k(1+n))2\pi\sqrt{m/(k(1+n))}Shorter piece, stiffer

B) Comparison of Oscillating Systems

SystemTime PeriodDepends OnIndependent Of
Spring-mass2πm/k2\pi\sqrt{m/k}Mass, spring constantAmplitude, gravity
Simple pendulum2πl/g2\pi\sqrt{l/g}Length, gravityMass, amplitude
Physical pendulum2πI/(mgl)2\pi\sqrt{I/(mgl)}MOI, distance to pivotAmplitude
Liquid in U-tube2πl/g2\pi\sqrt{l/g}Liquid column lengthDensity, cross-section
Floating body2πm/(ρlAg)2\pi\sqrt{m/(\rho_l Ag)}Mass, liquid density, areaDepth
Energy vs displacement in SHM — KE and PE parabolas crossing at x = A/√2, with constant total energy line

C) SHM Quantities at Key Positions

PositionDisplacementVelocityAccelerationKEPE
Mean (x=0x=0)0AωA\omega (max)0EE (max)0
Extreme (x=Ax=A)AA0Aω2A\omega^2 (max)0EE (max)
x=A/2x = A/2A/2A/232Aω\frac{\sqrt{3}}{2}A\omega12Aω2\frac{1}{2}A\omega^234E\frac{3}{4}E14E\frac{1}{4}E
x=A/2x = A/\sqrt{2}A/2A/\sqrt{2}12Aω\frac{1}{\sqrt{2}}A\omega12Aω2\frac{1}{\sqrt{2}}A\omega^212E\frac{1}{2}E12E\frac{1}{2}E

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