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Electromagnetic Induction & Lenz's Law

Apply concepts from Electromagnetic Induction & Lenz's Law to problem-solving. Focus on numerical practice, shortcuts, and real-world applications.

3%50 minPhase 2 · APPLICATIONMCQ + Numerical

Concept Core

Electromagnetic induction is the phenomenon where a changing magnetic flux through a circuit induces an EMF (and hence a current if the circuit is closed). Discovered by Faraday, this is the principle behind generators, transformers, and most of modern electrical technology.

Faraday's Law — Bar Magnet Moving Into a Coil:

Bar magnet approaching a coil inducing EMF (Faraday's law)

Faraday's Laws of Electromagnetic Induction:

First law: Whenever the magnetic flux through a circuit changes, an EMF is induced.
Second law: The induced EMF equals the negative rate of change of magnetic flux: ε=dΦBdt\varepsilon = -\frac{d\Phi_B}{dt}, where ΦB=BdA\Phi_B = \int \vec{B} \cdot d\vec{A}.
For a coil of NN turns: ε=NdΦBdt\varepsilon = -N\frac{d\Phi_B}{dt}. The flux can change due to change in BB, change in area AA, or change in the angle between B\vec{B} and A\vec{A}.

Lenz's Law: The direction of the induced current is such that it opposes the change in flux that produced it. This is a consequence of energy conservation — the induced current creates a magnetic field that opposes the flux change. Lenz's law is encoded in the negative sign of Faraday's law.

Motional EMF: When a conductor of length ll moves with velocity vv perpendicular to a uniform magnetic field BB: ε=Bvl\varepsilon = Bvl. This arises from the Lorentz force on free charges in the moving conductor.
For a rod sliding on rails: ε=Bvl\varepsilon = Bvl, current I=Bvl/RI = Bvl/R, force on rod F=BIl=B2l2v/RF = BIl = B^2l^2v/R, power dissipated P=B2l2v2/RP = B^2l^2v^2/R.

Rotating Coil (AC Generator): A coil of NN turns, area AA, rotating with angular velocity ω\omega in field BB: Φ=NBAcos(ωt)\Phi = NBA\cos(\omega t), ε=NBAωsin(ωt)\varepsilon = NBA\omega\sin(\omega t).
Peak EMF: ε0=NBAω\varepsilon_0 = NBA\omega. This produces alternating current.

Eddy Currents in a Metal Plate:

Eddy currents forming circular loops in a metal plate moving through a magnetic field

Eddy Currents: When a bulk conductor moves through a magnetic field (or is exposed to changing flux), circulating currents called eddy currents are induced. They cause heating (used in induction furnaces) and braking (electromagnetic damping). Laminated cores reduce eddy current losses.

Self-Inductance — Coil With Changing Flux:

Self-inductance: changing current in a coil produces back-EMF

Self-Inductance: A coil opposes changes in its own current.
ε=LdIdt\varepsilon = -L\frac{dI}{dt}, where LL is the self-inductance (unit: henry, H).
For a solenoid: L=μ0n2Al=μ0N2A/lL = \mu_0 n^2 Al = \mu_0 N^2 A/l, where ll is length, AA is cross-section, NN is total turns.

Mutual Inductance: Two coils interact through shared flux.
EMF in coil 2 due to changing current in coil 1: ε2=MdI1dt\varepsilon_2 = -M\frac{dI_1}{dt}.
For two coaxial solenoids: M=μ0n1n2AlM = \mu_0 n_1 n_2 A l (where AA is the area of the inner solenoid).
M=kL1L2M = k\sqrt{L_1 L_2} where kk is the coupling coefficient (0k10 \leq k \leq 1).

Energy Stored in an Inductor: U=12LI2U = \frac{1}{2}LI^2. Energy density in a magnetic field: u=B2/(2μ0)u = B^2/(2\mu_0) (analogous to u=ε0E2/2u = \varepsilon_0 E^2/2 for electric fields).

Key Testable Concept

**Energy Stored in an Inductor:** $U = \frac{1}{2}LI^2$. Energy density in a magnetic field: $u = B^2/(2\mu_0)$ (analogous to $u = \varepsilon_0 E^2/2$ for electric fields).

Comparison Tables

A) EMF Formulas

ConfigurationInduced EMFConditions
General Faraday's lawε=NdΦBdt\varepsilon = -N\frac{d\Phi_B}{dt}Any flux change
Moving rod in uniform BBε=Bvl\varepsilon = BvlRod   B\perp \; B, vlv \perp l
Rotating coilε=NBAωsin(ωt)\varepsilon = NBA\omega\sin(\omega t)Coil rotating in uniform BB
Self-inductionε=LdIdt\varepsilon = -L\frac{dI}{dt}Current changing in a coil
Mutual inductionε2=MdI1dt\varepsilon_2 = -M\frac{dI_1}{dt}Current in coil 1 changing

B) Inductance Formulas

ConfigurationInductanceNotes
SolenoidL=μ0n2Al=μ0N2A/lL = \mu_0 n^2 Al = \mu_0 N^2 A/lnn = turns/length
ToroidL=μ0N2A/(2πr)L = \mu_0 N^2 A/(2\pi r)rr = mean radius
Two coaxial solenoidsM=μ0n1n2AlM = \mu_0 n_1 n_2 A lAA = area of inner solenoid
Coupled coilsM=kL1L2M = k\sqrt{L_1 L_2}kk = coupling coefficient

C) Energy in Magnetic Fields

QuantityFormulaAnalogy
Energy in inductorU=12LI2U = \frac{1}{2}LI^2U=12CV2U = \frac{1}{2}CV^2 (capacitor)
Magnetic energy densityu=B22μ0u = \frac{B^2}{2\mu_0}u=ε0E22u = \frac{\varepsilon_0 E^2}{2} (electric)

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