MathematicsCG

Circles

Apply concepts from Circles to problem-solving. Focus on numerical practice, shortcuts, and real-world applications.

1-2 Qs/year50 minPhase 2 · APPLICATIONMCQ + Numerical

Concept Core

The circle is one of the most important conic sections in JEE Mathematics. A circle is the locus of a point moving at a constant distance (radius) from a fixed point (centre). Its study in coordinate geometry involves equations, tangents, normals, chord properties, and interactions with other circles and lines.

The standard form of a circle with centre (h, k) and radius r is (x - h)2 + (y - k)2 = r2r^{2}.
Expanding this gives the general form x2x^{2} + y2y^{2} + 2gx + 2fy + c = 0, where centre = (-g, -f) and radius = g2+f2c\sqrt{g^{2} + f^{2} - c}. For the circle to be real, g2g^{2} + f2f^{2} - c > 0.
When g2g^{2} + f2f^{2} = c, it degenerates to a point circle; when g2g^{2} + f2f^{2} < c, the circle is imaginary.

The position of a point P(x1, y1) relative to a circle x2x^{2} + y2y^{2} + 2gx + 2fy + c = 0 is determined by S1 = x12x1^{2} + y12y1^{2} + 2gx1 + 2fy1 + c.
If S1 < 0, the point is inside; S1 = 0, on the circle; S1 > 0, outside. The length of the tangent from an external point is S1\sqrt{S1}.

A line y = mx + c intersects the circle x2x^{2} + y2y^{2} = a2a^{2} when |c|/1+m2\sqrt{1 + m^{2}} < a, is tangent when |c|/1+m2\sqrt{1 + m^{2}} = a, and does not intersect when |c|/1+m2\sqrt{1 + m^{2}} > a.
The tangent at point (x1, y1) on x2x^{2} + y2y^{2} = a2a^{2} is xx1 + yy1 = a2a^{2} (obtained by the T = 0 formula).

The equation of the tangent to x2x^{2} + y2y^{2} = a2a^{2} with slope m is y = mx +/- a*1+m2\sqrt{1 + m^{2}}.
The chord of contact from an external point (x1, y1) is T = 0, i.e., xx1 + yy1 + g(x + x1) + f(y + y1) + c = 0.

Two circles S1 = 0 and S2 = 0 intersect at two points when |r1 - r2| < d < r1 + r2, where d is the distance between centres. They are tangent externally when d = r1 + r2 and internally when d = |r1 - r2|. The radical axis of two circles S1 - S2 = 0 is the locus of points having equal power with respect to both circles. The family of circles through the intersection of S1 and S2 is S1 + λ\lambda*S2 = 0.

The key problem-solving concept is mastering the T = 0 substitution (replacing x2x^{2} with xx1, y2y^{2} with yy1, x with (x+x1)/2, y with (y+y1)/2) which unifies tangent, chord of contact, chord with midpoint, and pair of tangents formulas.

Key Testable Concept

The key problem-solving concept is mastering the T = 0 substitution (replacing x^2 with xx1, y^2 with yy1, x with (x+x1)/2, y with (y+y1)/2) which unifies tangent, chord of contact, chord with midpoint, and pair of tangents formulas.

Study Materials

Available in the NoteTube app — start studying for free.

100 Flashcards

SM-2 spaced repetition flashcards with hints and explanations

100 Quiz Questions

Foundation and PYQ-style questions with AI feedback

15 Study Notes

Structured notes across 10 scientifically grounded formats

10 Summaries

Progressive summaries from comprehensive guides to cheat sheets

Continue studying in NoteTube

Frequently Asked Questions

Common questions about studying Circles for JEE Main 2027.

Circles — JEE Main 2027 Mathematics | NoteTube