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Chemical Kinetics: Rate Laws & Arrhenius Equation

Apply concepts from Chemical Kinetics: Rate Laws & Arrhenius Equation to problem-solving. Focus on numerical practice, shortcuts, and real-world applications.

4%50 minPhase 2 · APPLICATIONMCQ + Numerical

Concept Core

Chemical kinetics studies the speed of chemical reactions and the factors that influence them. JEE focuses heavily on rate law determination, integrated rate equations, half-life calculations, and the Arrhenius equation for temperature dependence.

Rate of Reaction: For aA + bB → cC + dD, rate = -(1/a)d[A]/dt = -(1/b)d[B]/dt = (1/c)d[C]/dt = (1/d)d[D]/dt. Instantaneous rate is the slope of the concentration-time curve at a given point. Average rate = δ\delta[product]/(δt\delta_{t}). Rate is always positive by convention.

Rate Law and Rate Constant: Rate = k[A]^m[B]^n, where m and n are orders (determined experimentally, NOT from stoichiometry). Overall order = m + n. The rate constant k depends on temperature but NOT on concentration. Units of k depend on order: for nth order, k has units of (concentration)^(1-n) time1time^{-1}.

Molecularity vs Order: Molecularity = number of reacting molecules in an elementary step (always a positive integer: 1, 2, or 3). Order = experimentally determined exponent in the rate law (can be zero, fractional, or negative). For elementary reactions: order = molecularity. For complex reactions: order is determined by the rate-determining step. Molecularity > 3 is not observed because simultaneous collision of >3 molecules is extremely improbable.

Zero Order Kinetics: Rate = k (independent of concentration). Integrated: [A] = [A]_0 - kt. Half-life: t12\frac{t_{1}}{2} = [A]_0/(2k). [A] vs t is a straight line with slope = -k. Example: decomposition of NH3 on Pt surface, photochemical reactions. Graph: [A] decreases linearly with time until [A] = 0.

First Order Kinetics: Rate = k[A]. Integrated: ln[A] = ln[A]_0 - kt, or k = (1/t)ln([A]_0/[A]) = (2.303/t)log([A]_0/[A]). Half-life: t12\frac{t_{1}}{2} = 0.693/k (independent of initial concentration). ln[A] vs t is linear with slope = -k. Examples: radioactive decay, decomposition of N2O5, H2O2 decomposition. First order is the most commonly tested order in JEE.

Second Order Kinetics: Rate = k[A]2. Integrated: 1/[A] = 1/[A]_0 + kt. Half-life: t12\frac{t_{1}}{2} = 1/(k[A]_0). 1/[A] vs t is linear with slope = k. Half-life depends on initial concentration (doubles when [A]_0 is halved).

Pseudo-First Order Reactions: A second (or higher) order reaction that behaves as first order because one reactant is in large excess. Example: acid hydrolysis of ester (CH3COOC2H5 + H2O), where [H2O] is essentially constant. Rate = k'[ester], where k' = k[H2O].

Ethyl acetate (CH3COOC2H5) — classic pseudo-first order hydrolysis substrate

Acetic acid — product of ethyl acetate hydrolysis

Ethanol — other product of hydrolysis

The overall reaction: CH3COOC2H5 + H2O → CH3COOH + C2H5OH

Arrhenius Equation: k = A * e^(-Ea/RT). A = pre-exponential factor (frequency factor), Ea = activation energy. ln(k) = ln(A) - Ea/(RT). Plot of ln(k) vs 1/T is linear with slope = -Ea/R. Two-temperature form: ln(k2/k1) = (Ea/R)(1/T1 - 1/T2). For every 10 K rise near room temperature, rate roughly doubles (temperature coefficient = 2-3).

Activation Energy: The minimum energy reactant molecules must possess to undergo a successful reaction. Ea(forward) - Ea(backward) = δH\delta_{H} (enthalpy of reaction). A catalyst lowers Ea for both forward and reverse reactions equally, without changing δH\delta_{H} or equilibrium constant. Ea is always positive.

Collision Theory: Rate = Z * f * e^(-Ea/RT), where Z = collision frequency, f = steric factor (fraction of collisions with correct orientation). Effective collisions require both sufficient energy (>= Ea) and proper orientation. The Boltzmann distribution shows that fraction of molecules with energy >= Ea increases exponentially with temperature.

Methods for Determining Order: (1) Initial rates method: compare rates at different initial concentrations. (2) Integrated rate law method: test which plot gives a straight line ([A] vs t for zero, ln[A] vs t for first, 1/[A] vs t for second). (3) Half-life method: if t12\frac{t_{1}}{2} is constant, order = 1; if t12\frac{t_{1}}{2} proportional to [A]_0, order = 0; if t12\frac{t_{1}}{2} proportional to 1/[A]_0, order = 2.

The key problem-solving concept is matching the correct integrated rate equation to the given data and applying the Arrhenius equation for temperature effects.

Key Testable Concept

The key problem-solving concept is matching the correct integrated rate equation to the given data and applying the Arrhenius equation for temperature effects.

Comparison Tables

A) Order Comparison

PropertyZero OrderFirst OrderSecond Order
Rate lawkk[A]k[A]2
Integrated[A]_0 - kt[A]_0 e^(-kt)1/([A]_0) + kt
Linear plot[A] vs tln[A] vs t1/[A] vs t
Slope-k-k+k
Half-life[A]_0/(2k)0.693/k1/(k[A]_0)
t12\frac{t_{1}}{2} depends on[A]_0Nothing[A]_0
Units of kmol/(L.s)s1s^{-1}L/(mol.s)

B) Key Arrhenius Relations

FormEquationUsage
Exponentialk = Ae^(-Ea/RT)Definition
Logarithmicln(k) = ln(A) - Ea/RTPlot ln(k) vs 1/T
Two-pointln(k2/k1) = (Ea/R)(1/T1 - 1/T2)Given k at two temperatures
Log formlog(k2/k1) = (Ea/2.303R)(1/T1 - 1/T2)JEE numerical convenience

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