Chemical Bonding: VSEPR, VBT & MOT
Apply concepts from Chemical Bonding: VSEPR, VBT & MOT to problem-solving. Focus on numerical practice, shortcuts, and real-world applications.
Concept Core
Chemical bonding determines molecular geometry, polarity, and reactivity. JEE Main tests three complementary theories: VSEPR (geometry prediction), VBT (orbital overlap and hybridisation), and MOT (bond order and magnetic behaviour).
Ionic vs Covalent Continuum: Fajans' rules quantify covalent character in ionic bonds. High covalent character arises from: small cation size, large anion size, high cation charge, pseudo-noble-gas configuration (e.g., Cu+, Ag+). LiI is more covalent than LiF; BeCl2 is more covalent than MgCl2.
VSEPR Theory: Electron pairs (bonding + lone pairs) around a central atom arrange to minimise repulsion. Repulsion order: lp-lp > lp-bp > bp-bp. The steric number (SN = bonding pairs + lone pairs on central atom) determines electron geometry. Molecular geometry depends on how many of those pairs are lone pairs.
SN = 2: linear (180 degrees). SN = 3: trigonal planar (120 degrees). SN = 4: tetrahedral (109.5 degrees). SN = 5: trigonal bipyramidal ( degrees). SN = 6: octahedral (90 degrees). SN = 7: pentagonal bipyramidal ( degrees).
Key VSEPR examples — linear vs bent geometry:
CO2 — linear (SN=2, no lone pairs on C)
H2O — bent geometry (SN=4, 2 lone pairs compress bond angle to 104.5 degrees)
Lone pairs occupy equatorial positions in TBP (they need more room). In octahedral arrangements with 2 lone pairs, they go trans to each other (square planar, e.g., XeF4).
Valence Bond Theory (VBT): Covalent bonds form by overlap of half-filled (or empty) atomic orbitals. Hybridisation is the mathematical mixing of orbitals to produce equivalent hybrid orbitals directed in space. Key hybridisations: sp (linear, BeCl2, C2H2), sp2 (trigonal planar, BF3, C2H4), sp3 (tetrahedral, CH4, NH3, H2O), sp3d (TBP, PCl5), sp3d2 (octahedral, SF6), sp3d3 (PBP, IF7).
Hybridisation examples — sp vs sp2 vs sp3:
Acetylene (C2H2) — sp hybridised carbons, linear, 180 degrees
Ethylene (C2H4) — sp2 hybridised carbons, trigonal planar, 120 degrees
Methane (CH4) — sp3 hybridised carbon, tetrahedral, 109.5 degrees
bonds form by head-on overlap; bonds by lateral overlap. In a double bond: 1 + 1 . In a triple bond: 1 + 2 .
Hybridisation of an atom = bonds + lone pairs on that atom (the steric number).
Molecular Orbital Theory (MOT): Atomic orbitals combine to form molecular orbitals (MOs). Number of MOs = number of AOs combined. Bonding MOs are lower in energy; antibonding MOs are higher. Bond order = (Nb - Na)/2, where Nb = electrons in bonding MOs, Na = electrons in antibonding MOs. If bond order = 0, the molecule is unstable.
For homonuclear diatomics up to N2 (Z <= 7), the (2p) MO is HIGHER in energy than (2p) MOs due to s-p mixing.
For O2 and beyond (Z >= 8), (2p) is LOWER than (2p). This is the critical ordering switch that explains O2's paramagnetism.
Dipole Moment and Polarity: = q * d (Debye units). Molecular polarity depends on both bond polarity AND geometry. Symmetric molecules (BF3, CCl4, XeF4) have zero net dipole despite polar bonds. Water (bent, 104.5 degrees) and NH3 (pyramidal, 107 degrees) have non-zero dipole moments.
Hydrogen Bonding: Strongest intermolecular force (5-40 kJ/mol). Requires H bonded to F, O, or N (highly electronegative, small atoms). Intramolecular H-bonding (e.g., o-nitrophenol) reduces boiling point relative to intermolecular H-bonding (p-nitrophenol).
Intramolecular vs intermolecular hydrogen bonding:
o-Nitrophenol — intramolecular H-bond (lower boiling point)
p-Nitrophenol — intermolecular H-bond (higher boiling point)
Coordinate (Dative) Bonds: Both electrons in the shared pair come from one atom (donor). Examples: NH4+ (N donates to H+), BF3.NH3, CO (C donates lone pair to form triple bond), O3 (central O donates to terminal O).
Key Testable Concept
**Coordinate (Dative) Bonds:** Both electrons in the shared pair come from one atom (donor). Examples: NH4+ (N donates to H+), BF3.NH3, CO (C donates lone pair to form triple bond), O3 (central O donates to terminal O).
Comparison Tables
A) VSEPR Geometry Summary
| SN | Lone Pairs | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|
| 2 | 0 | Linear | 180 | BeCl2, CO2 |
| 3 | 0 | Trigonal planar | 120 | BF3, SO3 |
| 3 | 1 | Bent (V-shape) | ~117 | SO2, SnCl2 |
| 4 | 0 | Tetrahedral | 109.5 | CH4, - |
| 4 | 1 | Trigonal pyramidal | ~107 | NH3, PCl3 |
| 4 | 2 | Bent (V-shape) | ~104.5 | H2O, H2S |
| 5 | 0 | Trigonal bipyramidal | 90, 120 | PCl5 |
| 5 | 1 | See-saw | ~90, ~120 | SF4 |
| 5 | 2 | T-shaped | ~90 | ClF3, BrF3 |
| 5 | 3 | Linear | 180 | XeF2, I3- |
| 6 | 0 | Octahedral | 90 | SF6 |
| 6 | 1 | Square pyramidal | ~90 | BrF5, IF5 |
| 6 | 2 | Square planar | 90 | XeF4, ICl4- |
B) MO Electron Configuration of Homonuclear Diatomics
| Species | Total e- | Bond Order | Magnetic Nature | Stable? |
|---|---|---|---|---|
| H2 | 2 | 1 | Diamagnetic | Yes |
| He2 | 4 | 0 | — | No |
| Li2 | 6 | 1 | Diamagnetic | Yes |
| B2 | 10 | 1 | Paramagnetic | Yes |
| C2 | 12 | 2 | Diamagnetic | Yes |
| N2 | 14 | 3 | Diamagnetic | Yes |
| O2 | 16 | 2 | Paramagnetic | Yes |
| F2 | 18 | 1 | Diamagnetic | Yes |
| Ne2 | 20 | 0 | — | No |
| O2+ | 15 | 2.5 | Paramagnetic | Yes |
| O2- | 17 | 1.5 | Paramagnetic | Yes |
| - | 18 | 1 | Diamagnetic | Yes |
| NO | 15 | 2.5 | Paramagnetic | Yes |
C) Hybridisation Quick Identification
| Formula | Central Atom | SN | Hybridisation | Geometry |
|---|---|---|---|---|
| BeCl2 | Be | 2 | sp | Linear |
| BF3 | B | 3 | sp2 | Trigonal planar |
| CH4 | C | 4 | sp3 | Tetrahedral |
| PCl5 | P | 5 | sp3d | Trigonal bipyramidal |
| SF6 | S | 6 | sp3d2 | Octahedral |
| IF7 | I | 7 | sp3d3 | Pentagonal bipyramidal |
| XeF2 | Xe | 5 | sp3d | Linear (3 lp) |
| XeF4 | Xe | 6 | sp3d2 | Square planar (2 lp) |
| XeO3 | Xe | 4 | sp3 | Trigonal pyramidal (1 lp) |
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