
Calculate the Acceleration of Two Blocks Connected by A String | Half Atwood Machine
INTEGRAL PHYSICS
Overview
This video explains how to calculate the acceleration and tension in a simplified "half Atwood machine" system. It involves a block on a horizontal surface connected by a string over a pulley to a hanging mass. The explanation focuses on drawing free-body diagrams for each mass, applying Newton's second law, and solving the resulting system of equations. The video emphasizes setting up a consistent direction of motion for both blocks and derives general formulas for acceleration and tension in terms of the masses and gravitational acceleration, assuming no friction or pulley mass.
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Chapters
- The problem involves two masses connected by a string over a pulley, a simplified version of the Atwood machine.
- The goal is to find the acceleration of both masses and the tension in the string.
- This specific scenario assumes no friction on the horizontal surface and no friction or mass in the pulley.
- For the block on the table (m1), forces are gravity (down), the normal force (up), and tension (right).
- Gravity on m1 (m1g) is balanced by the normal force because there's no vertical acceleration.
- For the hanging block (m2), forces are gravity (down) and tension (up).
- Crucially, the tension in the string is NOT equal to the weight of the hanging block (m2g) because the system is accelerating.
- Since the blocks are connected, they have the same magnitude of acceleration but in opposite directions (right for m1, down for m2).
- To apply Newton's second law consistently, define a positive direction of motion.
- The chosen positive direction is to the right for the block on the table and downward for the hanging block.
- Apply Newton's second law (ΣF = ma) to each block separately.
- For the block on the table (m1): Tension (T) = m1 * a (since net force is only tension in the defined positive direction).
- For the hanging block (m2): m2g - Tension (T) = m2 * a (since gravity is in the positive direction and tension is in the negative direction).
- Solve the system of two equations with two unknowns (a and T) using substitution.
- Solving the system yields an equation for acceleration: a = (m2 * g) / (m1 + m2).
- Substituting this acceleration back into the tension equation yields: T = (m1 * m2 * g) / (m1 + m2).
- These formulas allow calculation of acceleration and tension given the masses and gravitational acceleration.
Key takeaways
- Free-body diagrams are essential for visualizing and analyzing forces on individual objects.
- In a connected system, masses accelerate together, requiring a consistent definition of positive direction for all parts.
- Tension in a string connecting accelerating masses is not necessarily equal to the weight of any hanging portion.
- Newton's second law (ΣF = ma) must be applied to each mass individually.
- Solving a system of equations derived from Newton's second law allows for the determination of unknown variables like acceleration and tension.
- The derived formulas for acceleration and tension are valid only under the stated assumptions (no friction, massless pulley).
Key terms
Test your understanding
- What are the forces acting on the block resting on the table, and how do they relate if the block is not accelerating vertically?
- Why is it important to define a consistent direction of motion when analyzing the acceleration of connected masses?
- How does the tension in the string of a half Atwood machine differ from the weight of the hanging mass when the system is accelerating?
- What is the general formula for the acceleration of the two blocks in this system, and what assumptions does it rely on?
- How can you use the derived formula for acceleration to find the tension in the connecting string?