Part of JES-03 — Current Electricity: Ohm's Law, Kirchhoff's & Circuits

Special Circuit Problems

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JEE frequently features non-standard circuit topologies:

Cube of resistors: 12 equal resistors along edges. Between opposite corners: Req=5R/6R_{\text{eq}} = 5R/6 (by symmetry, identify three groups of parallel paths: 3, 6, 3 resistors). Between adjacent corners: Req=7R/12R_{\text{eq}} = 7R/12. Between face-diagonal corners: Req=3R/4R_{\text{eq}} = 3R/4.

Infinite ladder networks: Self-similar structure where adding one more section doesn't change the total. Set up equation Req=R1+R2ReqR_{\text{eq}} = R_1 + R_2 \| R_{\text{eq}} and solve the quadratic.

Symmetric circuits: Identify points at equal potential (by symmetry) and short them — zero current flows between equipotential points. This dramatically simplifies the circuit.

Star-delta transformation: Convert a Y-network (R1,R2,R3R_1, R_2, R_3) to delta (R12,R23,R31R_{12}, R_{23}, R_{31}) where R12=R1R2/R3+R1+R2R_{12} = R_1R_2/R_3 + R_1 + R_2 (and cyclic). For balanced networks: RΔ=3RYR_\Delta = 3R_Y.

Wire bent into shapes: A wire of total resistance RR bent into a circle gives Req=R/4R_{\text{eq}} = R/4 between diametrically opposite points (two R/2R/2 halves in parallel). Between adjacent points at angle θ\theta: Req=Rθ(2πθ)/(4π2)R_{\text{eq}} = R\theta(2\pi - \theta)/(4\pi^2).

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