Part of JWAVE-01 — Simple Harmonic Motion

SHM Problem-Solving Strategies for JEE

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For JEE SHM problems, follow a systematic approach. Step 1: Identify the restoring force. Displace the system by xx from equilibrium and compute the net force. If F=kxF = -kx, it is SHM with ω=k/m\omega = \sqrt{k/m}. Step 2: For complex systems (pulleys, levers, floating bodies), use the energy method. Write total energy E=12meffx˙2+12keffx2E = \frac{1}{2}m_{\text{eff}}\dot{x}^2 + \frac{1}{2}k_{\text{eff}}x^2 and extract T=2πmeff/keffT = 2\pi\sqrt{m_{\text{eff}}/k_{\text{eff}}}.

Step 3: For velocity/acceleration at a position, use v=ωA2x2v = \omega\sqrt{A^2-x^2} and a=ω2xa = -\omega^2 x directly. Step 4: For energy partition, use KE/E=1x2/A2KE/E = 1-x^2/A^2 and PE/E=x2/A2PE/E = x^2/A^2. Step 5: For time calculations, use the reference circle method.

Common traps to avoid: (1) Using pendulum formula for spring systems or vice versa. (2) Forgetting that cutting a spring changes kk. (3) Not replacing gg with geffg_{\text{eff}} in non-inertial frames (for pendulums). (4) Confusing KE = PE position (A/2A/\sqrt{2}) with KE = 3PE position (A/2A/2). (5) Assuming time is proportional to distance in SHM. Always verify dimensions of your answer and check limiting cases.

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