• $summary_{type}$: application
• $word_{count}$: 150

A tuning fork of frequency f is held over a tube with adjustable water level. Resonance (loud sound) occurs at: $l_1$ + e = lambda/4 (first), $l_2$ + e = 3lambda/4 (second). Taking the difference: lambda = 2($l_2$ - $l_1$), eliminating end correction e. Speed: v = flambda = 2f*($l_2$ - $l_1$). End correction: e = $\frac{l_2 - 3*l_1}{2}$ ≈ 0.3d (tube diameter). Verification: $l_3$ - $l_2$ should equal $l_2$ - $l_1$ = lambda/2. Speed of sound depends on temperature: v = 331 + 0.6T(degrees C) m/s. The resonance tube works with open-end correction — the antinode forms slightly outside the tube. For accurate results, use a narrow tube (smaller end correction) and bring the tuning fork close to the tube opening without touching. JEE may ask for end correction calculation or speed of sound at a given temperature.