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Part of PH-01 — Dual Nature of Radiation & Matter

PH-01 Complete Formula Reference with Dimensional Analysis

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Photoelectric Effect

KEmax⁡=hν−ϕ[ML2T−2]J or eVKE_{\max} = h\nu - \phi \quad [ML^2T^{-2}] \quad \text{J or eV}

eV0=hν−ϕ  ⟹  V0=hν−ϕe[ML2T−3A−1]VeV_0 = h\nu - \phi \implies V_0 = \frac{h\nu - \phi}{e} \quad [ML^2T^{-3}A^{-1}] \quad \text{V}

ν0=ϕh[T−1]Hzλ0=hcϕ=1240ϕ(eV) nm[L]m\nu_0 = \frac{\phi}{h} \quad [T^{-1}] \quad \text{Hz} \qquad \lambda_0 = \frac{hc}{\phi} = \frac{1240}{\phi(\text{eV})} \text{ nm} \quad [L] \quad \text{m}

KEmax⁡ from wavelengths:KEmax⁡=hc(1λ−1λ0)[ML2T−2]KE_{\max} \text{ from wavelengths:} \quad KE_{\max} = hc\left(\frac{1}{\lambda} - \frac{1}{\lambda_0}\right) \quad [ML^2T^{-2}]

Photon Properties

E=hν=hcλ=1240λ(nm) eV[ML2T−2]E = h\nu = \frac{hc}{\lambda} = \frac{1240}{\lambda(\text{nm})} \text{ eV} \quad [ML^2T^{-2}]

p=hλ=Ec=hνc[MLT−1]kg m/sp = \frac{h}{\lambda} = \frac{E}{c} = \frac{h\nu}{c} \quad [MLT^{-1}] \quad \text{kg m/s}

de Broglie Wavelength

λ=hmv=hp[L]m\lambda = \frac{h}{mv} = \frac{h}{p} \quad [L] \quad \text{m}

λ=h2m⋅KE[L]λe=1.227V nm (electrons only)\lambda = \frac{h}{\sqrt{2m \cdot KE}} \quad [L] \qquad \lambda_e = \frac{1.227}{\sqrt{V}} \text{ nm (electrons only)}

λ=h2mqV(any particle, charge q)λthermal=h3mkT[L]\lambda = \frac{h}{\sqrt{2mqV}} \quad \text{(any particle, charge q)} \qquad \lambda_{\text{thermal}} = \frac{h}{\sqrt{3mkT}} \quad [L]

Ratios and Comparisons

λ1λ2=m2q2m1q1 (same V)λeλp≈42.8λeλα≈121\frac{\lambda_1}{\lambda_2} = \sqrt{\frac{m_2 q_2}{m_1 q_1}} \text{ (same V)} \qquad \frac{\lambda_e}{\lambda_p} \approx 42.8 \qquad \frac{\lambda_e}{\lambda_\alpha} \approx 121

Key Constants

h=6.63×10−34 J⋅s[ML2T−1]hc=1240 eV⋅nmh = 6.63 \times 10^{-34} \text{ J·s} \quad [ML^2T^{-1}] \qquad hc = 1240 \text{ eV·nm}

e=1.6×10−19 Cme=9.1×10−31 kgmp=1.67×10−27 kge = 1.6 \times 10^{-19} \text{ C} \quad m_e = 9.1 \times 10^{-31} \text{ kg} \quad m_p = 1.67 \times 10^{-27} \text{ kg}

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