Part of CALC-02 — Methods of Differentiation

Parametric Curves and Their Derivatives

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Parametric representation expresses a curve using a parameter t: x = f(t), y = g(t). This is natural for many curves like circles, ellipses, and cycloids.

Key Parametric Curves in JEE:

Circle: x = acos t, y = asin t. dy/dx = -cot t. d2yd^{2y}/dx2dx^2 = -cosec^3$$\frac{t}{a}.

Ellipse: x = acos t, y = bsin t. dy/dx = -ba\frac{b}{a}*cot t. The tangent equation at parameter t: xcosta\frac{x*cos t}{a} + ysintb\frac{y*sin t}{b} = 1.

Parabola: x = at2at^2, y = 2at. dy/dx = 1/t. The tangent equation at (at2at^2, 2at): ty = x + at2at^2.

Cycloid: x = a(t-sin t), y = a(1-cos t). dy/dx = sin t1cost\frac{t}{1-cos t} = cott2\frac{t}{2}. This curve is generated by a point on a rolling circle.

Astroid: x = a*cos3cos^3(t), y = a*sin3sin^3(t). dy/dx = -tan t. This is a hypocycloid with four cusps.

Involute of circle: x = a(cos t + tsin t), y = a(sin t - tcos t). dy/dx = tan t.

Second Derivative Computation:

  1. Find dy/dx as a function of t
  2. Differentiate dy/dx with respect to t to get ddy/dxdt\frac{dy/dx}{dt}
  3. Divide by dx/dt: d2yd^{2y}/dx2dx^2 = [ddy/dxdt\frac{dy/dx}{dt}] / [dx/dt]

Common Error: Students write d2yd^{2y}/dx2dx^2 = d2y/dt2(d2x/dt2)\frac{d^2y/dt^2}{(d^2x/dt^2)}. This is WRONG and will give incorrect answers. The correct formula treats dy/dx as a single entity to be differentiated with respect to t.

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