When speed changes along the circular path, two perpendicular accelerations exist:

Centripetal (radial): $a_c$ = $v^2$/r, always toward the centre. Tangential: $a_t$ = $\frac{dv}{dt}$, along the direction of motion (or opposite if decelerating).

Net acceleration: a = sqrt($a_c^2$ + $a_t^2$), at angle phi = arctan$\frac{a_t}{a_c}$ from the radius.

Angular kinematics (constant alpha): omega = $omega_0$ + alphat theta = $omega_0$t + $\frac{1}{2}$alpha$t^2$ $omega^2$ = $omega_0^2$ + 2alphatheta

Key point: The net force is NOT directed toward the centre in non-uniform circular motion. Only the radial component is centripetal.