Part of CG-06 — Coordinate Geometry: Locus & Transformation

Locus Problems Involving Conics

by Notetube Officialdetailed summary280 words9 views

Several standard locus results involving conics appear repeatedly in JEE. These form the "ready reckoner" of conic-related loci.

Locus of the foot of perpendicular from focus to tangent: For a parabola y2y^2=4ax, this locus is the tangent at the vertex (x=0, the y-axis). For an ellipse or hyperbola x2x^2/a2+a^{2+}/-y2y^2/b2b^2=1, the locus is the auxiliary circle x^{2+y}^2=a2a^2.

Locus of intersection of perpendicular tangents directorcircledirectrix\frac{director circle}{directrix}: For a circle x^{2+y}^2=r2r^2, it is x^{2+y}^2=2r2r^2. For an ellipse x2x^2/a^{2+y}^2/b2b^2=1, it is x^{2+y}^2=a^{2+b}^2. For a hyperbola x2x^2/a^{2-y}^2/b2b^2=1, it is x^{2+y}^2=a^{2-b}^2 (exists only when a>b). For a parabola y2y^2=4ax, it is the directrix x=-a.

Locus of the midpoint of a focal chord: For the parabola y2y^2=4ax, the locus is y2y^2=2a(x-a).

Locus of the intersection of tangents at the ends of a focal chord: For y2y^2=4ax, the tangents at (at12at1^2,2at1) and (at22at2^2,2at2) with t1*t2=-1 meet at (-a, a(t1+t2)). The locus is x=-a, the directrix.

The T=S1 method for chord midpoint problems: for a chord of a circle x^{2+y}^2=r2r^2 with midpoint (h,k), the chord equation is hx+ky=h^{2+k}^2. Apply the additional condition (passes through a point, subtends a given angle, etc.) to obtain the locus.

Apollonius circle: If PA/PB=k (constant, k!=1) where A and B are fixed points, the locus is a circle. When k=1, the locus degenerates to the perpendicular bisector of AB.

Want to generate AI summaries of your own documents? NoteTube turns PDFs, videos, and articles into study-ready summaries.

Sign up free to create your own