Part of JTHERM-01 — Thermodynamics: Laws, Processes & Engines

JEE Problem-Solving Strategy

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Step 1 — Identify the process: Look for keywords — "insulated" (adiabatic), "slowly" (quasi-static/isothermal if in thermal contact), "rigid container" (isochoric), "piston free to move" (often isobaric). If PVn=CPV^n = C is given, it is polytropic.

Step 2 — Apply the First Law: Q=ΔU+WQ = \Delta U + W. For ideal gases, ΔU=nCvΔT\Delta U = nC_v\Delta T always. Calculate WW using the process-specific formula. Find the third quantity.

Step 3 — Cyclic processes: ΔU=0\Delta U = 0 (state function returns to start), so Qnet=Wnet=Q_{\text{net}} = W_{\text{net}} = area enclosed on P-V diagram. Clockwise = positive work (engine), anticlockwise = negative work.

Step 4 — Carnot problems: Always convert to Kelvin first. Use η=1TC/TH\eta = 1 - T_C/T_H. For combined engine-refrigerator problems, the work output of one drives the other.

Common traps: (1) Using Celsius in Carnot formula. (2) Confusing WW done "by" vs "on" the gas. (3) Applying ΔU=nCvΔT\Delta U = nC_v\Delta T only to isochoric — it works for all ideal gas processes. (4) Forgetting that free expansion has W=0W = 0 (no opposing pressure). (5) In mixing problems, use Tf=(n1Cv1T1+n2Cv2T2)/(n1Cv1+n2Cv2)T_f = (n_1C_{v1}T_1 + n_2C_{v2}T_2)/(n_1C_{v1} + n_2C_{v2}) for gases in an insulated container.

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