• $summary_{type}$: application
• $word_{count}$: 160

Standard form: E = $E_0$ sin(kz - omegat) x-hat, B = $B_0$ sin(kz - omegat) y-hat. Here k = 2pi/lambda (wave number), omega = 2pif (angular frequency), v = $\frac{omega}{k}$ = c. The propagation direction is along E x B (use right-hand rule). Given E direction and propagation direction, find B: B = $\frac{k-hat x E}{c}$, where k-hat is the unit propagation vector. Key relationships: $E_0$ = c$B_0$, lambdaf = c, omega = ck. To identify the wave type: check lambda against the spectrum table. JEE problems typically give E (or B) and ask you to write B (or E), identify propagation direction, calculate intensity, or find the radiation pressure. Strategy: (1) Extract $E_0$, k, omega from the given expression. (2) Compute lambda = 2pi/k, f = $\frac{omega}{2*pi}$. (3) Verify c = $\frac{omega}{k}$. (4) $B_0$ = $\frac{E_0}{c}$. (5) Use right-hand rule for direction.