• summary_type: application
• word_count: 160

Standard form: E = E_0 sin(kz - omegat) x-hat, B = B_0 sin(kz - omegat) y-hat. Here k = 2pi/lambda (wave number), omega = 2pif (angular frequency), v = omega/k = c. The propagation direction is along E x B (use right-hand rule). Given E direction and propagation direction, find B: B = (k-hat x E)/c, where k-hat is the unit propagation vector. Key relationships: E_0 = cB_0, lambdaf = c, omega = ck. To identify the wave type: check lambda against the spectrum table. JEE problems typically give E (or B) and ask you to write B (or E), identify propagation direction, calculate intensity, or find the radiation pressure. Strategy: (1) Extract E_0, k, omega from the given expression. (2) Compute lambda = 2pi/k, f = omega/(2*pi). (3) Verify c = omega/k. (4) B_0 = E_0/c. (5) Use right-hand rule for direction.