Critical JEE Traps in Gravitation

g at height h = R is g/4 $\frac{NOT g}{2}$ — inverse square, not inverse
Escape velocity is independent of mass AND direction of projection
$v_e$ from orbit = sqrt(2)* $v_{orbital}$ (not sqrt(2gR))
Using g(1-2h/R) when h is comparable to R gives wrong (even negative) results
PE = mgh is wrong for large heights — use U = -GMm/r
Astronauts in orbit HAVE weight (mg is not zero) — they have zero apparent weight
Gravitational PE is always negative (zero at infinity)
Same dimensions for height and depth reduction of g does NOT mean same formula
The null point between Earth and Moon is closer to the Moon (lighter body)
Geostationary orbit must be equatorial (not just T = 24h)