Part of ALG-04 — Probability & Distributions

Complete Chapter Overview

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Probability contributes 2-3 questions annually in JEE Main, spanning classical probability, conditional probability, Bayes' theorem, and binomial distribution. The chapter requires both counting skills and probability framework identification.

Classical probability uses P(A) = nAn\frac{A}{n}(S) for equally likely outcomes. The complement rule P(A') = 1 - P(A) is the fastest approach for "at least one" problems. The addition rule P(A union B) = P(A) + P(B) - P(A intersect B) handles unions, simplifying for mutually exclusive events where the intersection is zero.

Conditional probability P(A|B) = PAintersectBP\frac{A intersect B}{P}(B) restricts the sample space. Independence requires P(A intersect B) = P(A)*P(B). A critical distinction: mutually exclusive events with non-zero probabilities are NEVER independent.

Bayes' theorem reverses conditional probability: P(BiB_i|A) = P(A|BiB_i)*PBiP\frac{B_i}{P}(A), using total probability in the denominator. Common JEE applications include defective items from multiple machines and ball-drawing from multiple bags.

The binomial distribution B(n,p) models n independent trials with P(X=r) = C(n,r)*prp^r*q^(n-r). Mean = np, Variance = npq. The mode lies near (n+1)p.

Key problem-solving strategy: first identify the probability framework (classical counting, conditional, Bayes', or binomial), then apply the appropriate formula systematically.

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