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Part of PC-03 — Chemical Bonding & Molecular Structure

Chemical Bonding & Molecular Structure — Visual Guide

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### Concept Map: Bonding Framework ```mermaid graph TD A[Chemical Bonding] --> B[Ionic Bonding] A --> C[Covalent Bonding] B --> D[Born-Haber Cycle\n$\Delta Hf$ = $\Delta Hs$ub + IE + ½$\Delta Hd$iss + EA + U] B --> E[Fajan's Rules\nSmall cation + Large anion\n= More covalent character] C --> F[VSEPR Theory\nSN = σ-bonds + lone pairs] C --> G[Hybridization\nSN 2→sp ... SN 6→$sp^{3}$$d^{2}$] C --> H[MOT\nBO = Nb-Na / 2] F --> I[Molecular Shape\nRemove lone pairs from\nelectron geometry] H --> J[$O_{2}$ Paramagnetic\n2 unpaired $e^{-}$ in π*2p] ``` ### VSEPR Shape Decision Table | Lone Pairs on Central Atom | SN=4 Shape | SN=5 Shape | SN=6 Shape | |---|---|---|---| | 0 | Tetrahedral (109.5°) | Trigonal bipyramidal | Octahedral (90°) | | 1 | Trigonal pyramidal (~107°) ↓ | See-saw (~90°/120°) ↓ | Square pyramidal (~90°) ↓ | | 2 | Bent (~104.5°) ↓↓ | T-shape (~90°) ↓↓ | Square planar (90°) ↓↓ | | 3 | — | Linear (180°) ↓↓↓ | — | (↓ = bond angle compressed relative to ideal by lone pair repulsion) ### MO Energy Level Comparison | Feature | Z ≤ 7 ($B_{2}$, $C_{2}$, $N_{2}$) | Z > 7 ($O_{2}$, $F_{2}$) | |---|---|---| | 2p MO order | π2p **below** σ2p | σ2p **below** π2p | | Key difference | π2p fills first (mixing) ↑ | σ2p fills first (normal) ↑ | | Affected BO | $N_{2}$ BO = 3 (correct only with mixing order) | $O_{2}$ BO = 2 | | Magnetism | $N_{2}$ diamagnetic | $O_{2}$ paramagnetic | ### Dipole Moment: Zero vs Non-Zero | μ = 0 (symmetric) | μ ≠ 0 (asymmetric or lone pair) | |---|---| | C$O_{2}$ — linear | $H_{2}O$ — bent (lone pairs) | | $BF_{3}$ — trigonal planar | $NH_{3}$ — pyramidal (lone pair) | | $CCl_{4}$ — tetrahedral | $CHCl_{3}$ — tetrahedral but asymmetric bonds | | $SF_{6}$ — octahedral | S$O_{2}$ — bent (lone pair) | ### Born-Haber Cycle for NaCl (Energy Ladder) ``` Na(g) + ½$Cl_{2}$(g) ──(+121 kJ ½$\Delta Hd$iss)──► Na(g) + Cl(g) ↑ +108 kJ (sublimation) ↓ −349 kJ (EA) Na(s) + ½$Cl_{2}$(g) $Na^{+}$(g) + $Cl^{-}$(g) ↑ $\Delta Hf$ = −411 kJ ↓ U = −787 kJ Na(s) + ½$Cl_{2}$(g) ←──────── NaCl(s) ``` $$U = \Delta H_f - \Delta H_{sub} - \frac{1}{2}\Delta H_{diss} - IE - EA = -787 \text{ kJ/mol}$$$

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