Part of OC-06 — Aldehydes & Ketones

Aldehydes & Ketones: Previous Year Question Trends (NEET 2017-2024)

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High-Frequency Pattern 1: Iodoform Test (appears almost every year)

The question usually lists 4-5 compounds and asks which give positive iodoform test. Guaranteed answer set: any compound with CH3CO- group OR ethanol OR isopropanol. Guaranteed negative: methanol, propan-1-ol, diethyl ketone, formaldehyde, benzaldehyde. Strategy: check each compound for CH3CO- group or oxidizable to CH3CO-.

High-Frequency Pattern 2: Aldol vs Cannizzaro (appears every 2-3 years)

The question names a specific aldehyde + NaOH and asks for the reaction/product. Strategy: instantly check for alpha-H. HCHO → Cannizzaro (no alpha-C). C6H5CHO → Cannizzaro (adjacent C is benzene ring). CH3CHO → Aldol. ((CH3)3CCHO) → Cannizzaro (quaternary alpha-C, no H). Never choose "aldol" for benzaldehyde.

High-Frequency Pattern 3: Tollens' Test Specificity (alternate years)

"Which gives a silver mirror?" — The answer is always the aldehyde in the list. Common distractor: acetone or another ketone with positive iodoform (but still negative for Tollens'). Acetophenone is negative Tollens' (ketone) even though it's positive iodoform.

High-Frequency Pattern 4: Reduction Method Selection

"Which reagent converts C=O to CH2?" — Clemmensen or Wolff-Kishner. "Which gives alcohol?" — NaBH4 or LiAlH4. "Which is acidic?" — Clemmensen (Zn-Hg/HCl). "Which is basic?" — Wolff-Kishner NH2NH2KOH\frac{NH2NH2}{KOH}.

Recently Tested (2022-2024): Reactivity Order

Questions on ordering HCHO, CH3CHO, (CH3)2CO by reactivity in nucleophilic addition. Correct: HCHO > CH3CHO > (CH3)2CO. Reason: +I effect and steric hindrance of increasing alkyl groups.

One Sentence Rule for Each Pattern:

  • Iodoform: "CH3CO- group or oxidizable to it = YES"
  • Aldol vs Cannizzaro: "Alpha-H = Aldol; No alpha-H = Cannizzaro"
  • Tollens': "Aldehyde only = silver mirror"
  • Reduction: "NaBH4 = alcohol; Clemmensen/WK = CH2"

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