The magnifying power of a simple microscope is 6. The focal length of the lens is:

The angular magnification of a telescope is given by M = 12. If the objective has focal length 240 cm, the focal length of the eyepiece is:

Which instrument is used to view very distant objects?

The magnifying power of an astronomical telescope in normal adjustment is 10. If the focal length of the objective is 100 cm, the focal length of the eyepiece is: <svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 350 100" style="max-width:350px;margin:0.5em auto;display:block;"> <title>Astronomical telescope in normal adjustment — objective and eyepiece with tube length f_o + f_e</title> <rect width="350" height="100" fill="#faf9f5" rx="6"/> <line x1="20" y1="50" x2="330" y2="50" stroke="#14140f" stroke-width="0.7" stroke-dasharray="3,3"/> <ellipse cx="60" cy="50" rx="4" ry="28" fill="none" stroke="#14140f" stroke-width="1.5"/> <text x="60" y="88" text-anchor="middle" font-size="8" fill="#14140f">f_o = 100</text> <ellipse cx="280" cy="50" rx="3" ry="16" fill="none" stroke="#14140f" stroke-width="1.5"/> <text x="280" y="88" text-anchor="middle" font-size="8" fill="#14140f">f_e = ?</text> <text x="170" y="20" text-anchor="middle" font-size="9" fill="#788c5d">M = f_o/f_e = 10</text> </svg>

A telescope objective has a diameter of 122 cm. The minimum angular separation it can resolve at wavelength 5000 Å is: