Hydrocarbons: Alkanes, Alkenes & Alkynes — Advanced + PYQ-Style (50 Questions, Hard, 45 min)
Practice 100 questions on Hydrocarbons: Alkanes, Alkenes & Alkynes — Advanced + PYQ-Style (50 Questions, Hard, 45 min). Includes: The % s-character of the C–H bond in ethene (`C=C`) is:; To remember Lindlar (cis) vs Na/NH₃ (trans), a useful…; The SMILES notation `CCCBr` corresponds to:. Free quiz on NoteTube.
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- 1.
**Assertion (A):** The anti conformation of butane is more stable than the gauche conformation. **Reason (R):** In the anti conformation, the two methyl groups are at 180°, minimizing steric and torsional strain.
- 2.
**Assertion (A):** Anti-Markovnikov addition of HBr to propene in the presence of peroxide gives 1-bromopropane. **Reason (R):** In the presence of peroxide, the reaction proceeds by a free radical mechanism where H• adds first to the less substituted carbon.
- 3.
**Assertion (A):** In free radical halogenation, the termination step increases the concentration of the halogen radical (X•). **Reason (R):** Termination involves combination of two radicals to form a stable molecule.
- 4.
**Assertion (A):** Anti-Markovnikov addition does not occur when HCl reacts with propene in the presence of peroxide. **Reason (R):** Cl• radical addition to the alkene double bond is an endothermic step, making the free radical chain energetically unfavorable for HCl.
- 5.
The SMILES notation `CCCBr` corresponds to:
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