JEE PYQ Pattern Mix

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  1. 1.

    f(x) = {sin(pi*x/2), x<1; [x]*(-1)^([x]+1), x>=1}. At x=1, f is:

  2. 2.

    The equation x*e^x = 2 has a root in:

  3. 3.

    f(x)=|x^3|. At x=0:

  4. 4.

    If f(x)=2x^3-3x^2-12x+4, the equation f'(x)=0 has roots at:

  5. 5.

    f(x) = {(|x|-3), x<1; (|x-2|+a), x>=1} is continuous at x=1. Then a=:

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