JEE PYQ Pattern Mix

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  1. 1.

    lim(x->inf) x * [sqrt(x^2 + 1) - sqrt(x^2 - 1)] equals:

  2. 2.

    lim(n->inf) (1 + 1/n)^n equals:

  3. 3.

    If f(x) is continuous at x = 0 and f(0) = 2, then lim(x->0) f(x)/x:

  4. 4.

    lim(x->0) (1 - cos x * cos 2x * cos 3x)/x^2 equals:

  5. 5.

    lim(x->0) (sin(pi*cos^2 x))/x^2 equals:

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