Problem 1: Motional EMF with Force
Given: Rod length l = 50 cm = 0.50 m, velocity v = 4 m/s, field B = 0.5 T, resistance R = 2 Ω.
Step 1 — Motional EMF:
ε=Bvl=0.5T×4m/s×0.50m=1.0V
Step 2 — Induced current:
I=Rε=2Ω1.0V=0.5A
Step 3 — Force on rod (Lenz's law: opposing motion):
F=BIl=0.5T×0.5A×0.50m=0.125N
Step 4 — Power check (energy conservation):
Pexternal=Fv=0.125×4=0.5W
Pdissipated=I2R=(0.5)2×2=0.5W✓