If in $x^2$/$a^2$ + $y^2$/$b^2$ = 1, we have b > a, then the major axis is along the y-axis. In this case, foci are at (0, +/-c) where $c^2$ = $b^2$ - $a^2$, eccentricity e = $\frac{c}{b}$, vertices at (0, +/-b), and LR = 2$a^2$/b. Always identify the larger denominator as the square of the semi-major axis. This is a common source of errors in JEE.