If in x^2/a^2 + y^2/b^2 = 1, we have b > a, then the major axis is along the y-axis. In this case, foci are at (0, +/-c) where c^2 = b^2 - a^2, eccentricity e = c/b, vertices at (0, +/-b), and LR = 2a^2/b. Always identify the larger denominator as the square of the semi-major axis. This is a common source of errors in JEE.