Part of ME-04 — Work, Energy & Power

Vertical Circular Motion: Diagram and Analysis

by Notetube Official399 words8 views

Forces at Key Points

R TOP T + mg → centre BOTTOM T − mg = $mv^{2}$/R SIDE v = √(3gR) Min Speeds (string) Top: √(gR) Side: √(3gR) Bottom: √(5gR) Tb − Tt = 6mg Min Speeds (rod) Top: 0 Bottom: √(4gR) = 2√(gR) v (tangential)

String vs. Rod — Key Distinction

A string can only pull (tensile force). Minimum tension = 0 at the top ⟹ v_top ≥ √(gR).

A rigid rod can push (compressive) or pull. At the top with v = 0: rod pushes inward, providing centripetal force. So v_top,min = 0.

Tension Difference Formula

TbottomTtop=6mg(independent of v, m, R)T_{\text{bottom}} - T_{\text{top}} = 6mg \quad \text{(independent of v, m, R)}

This is a powerful check formula — always valid for any speed (not just minimum).

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes