Part of OC-09 — Biomolecules

| Type: Concept Note

by Notetube Official207 words7 views

Reducing vs Non-Reducing Sugars: Complete Analysis

Definition: A reducing sugar has a free anomeric carbon that can exist in the open-chain (hemiacetal/hemiketal) form, exposing a free aldehyde or alpha-hydroxy ketone group capable of reducing oxidising agents.

Tests for reducing sugars:

  • Tollens' test: Ag+Ag^{+} (in ammonia) → Ag0Ag^{0} (silver mirror)
  • Fehling's test: Cu2+Cu^{2+} (deep blue) → Cu2OCu_{2}O (brick-red precipitate)
  • Benedict's test: Similar to Fehling's (Cu2+Cu^{2+}Cu2OCu_{2}O)

Reducing sugar equilibrium: cyclic form (hemiacetal)open-chain form (aldehyde)reduces oxidant\text{cyclic form (hemiacetal)} \rightleftharpoons \text{open-chain form (aldehyde)} \rightarrow \text{reduces oxidant}

Key disaccharides — NEET table:

SugarUnitsLinkageReducing?Why
SucroseGlc + Frualpha-1,2 (C1↔C2)NoBoth anomeric Cs in bond
LactoseGal + Glcbeta-1,4 (C1→C4)YesFree C1 of Glc unit
MaltoseGlc + Glcalpha-1,4 (C1→C4)YesFree C1 of 2nd Glc unit

Critical NEET trap: Fructose IS a reducing sugar even though it is a ketose (ketohexose). Under alkaline conditions of Fehling's/Tollens' tests, the alpha-hydroxy ketone undergoes keto-enol tautomerism:

D-Fructose (ketose)baseEnediol intermediateD-Glucose + D-Mannose (aldoses)\text{D-Fructose (ketose)} \xrightarrow{\text{base}} \text{Enediol intermediate} \rightarrow \text{D-Glucose + D-Mannose (aldoses)}

The aldoses generated reduce the reagent. Therefore "ketoses are non-reducing" is FALSE for free fructose.

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