If a cevian AD divides BC into BD:DC = m:n, and angle ADC = theta, angle BAD = alpha, angle DAC = beta, then: (m+n)cot(theta) = mcot(alpha) - ncot(beta) and (m+n)cot(theta) = ncot(B) - mcot(C). This provides angle relationships involving the cevian.
Part of TRIG-03 — Properties of Triangles & Heights-Distances
The m-n Theorem for Cevian Angles
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