The tangent to x^{2+y}^2= with slope m is y = mx +/- asqrt(1+). The point of tangency for y=mx+asqrt(1+) is (-am/sqrt(1+), a/sqrt(1+)). For circle (x-h)^2+(y-k)^2=, the tangent with slope m is y-k = m(x-h) +/- r*sqrt(1+). This is used when the slope is specified or when a line from an external point must be tangent.
Part of CG-02 — Circles
Tangent with Given Slope
Like these notes? Save your own copy and start studying with NoteTube's AI tools.
Sign up free to clone these notes