Part of CG-02 — Circles

Tangent with Given Slope

by Notetube Official55 words4 views

The tangent to x^{2+y}^2=a2a^2 with slope m is y = mx +/- asqrt(1+m2m^2). The point of tangency for y=mx+asqrt(1+m2m^2) is (-am/sqrt(1+m2m^2), a/sqrt(1+m2m^2)). For circle (x-h)^2+(y-k)^2=r2r^2, the tangent with slope m is y-k = m(x-h) +/- r*sqrt(1+m2m^2). This is used when the slope is specified or when a line from an external point must be tangent.

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