• id: JME-10-N10
• title: Mixing Steam and Ice — Step-by-Step Method
• tags: steam, ice, mixing, phase-change

Strategy: (1) Calculate total heat available from the hot body (including latent heats). (2) Calculate total heat needed by the cold body (including latent heats). (3) Compare to determine which phase changes complete.

Example: Steam at 100 degrees C + Ice at 0 degrees C. Heat released by 1 g steam: condensation (540 cal) + cooling to 0 degrees C (100 cal) = 640 cal. Heat needed by 1 g ice: melting (80 cal) + heating to 100 degrees C (100 cal) = 180 cal. Since 640 > 180, steam can handle much more ice. If quantities are equal, not all steam condenses — find the equilibrium temperature between 0 and 100 degrees C where energies balance.