A conducting rod slides on two parallel rails in a uniform field $B$ perpendicular to the rail plane. Key results: EMF $= Bvl$, current $= Bvl/(R + r)$ where $R$ is external resistance and $r$ is rod resistance. The force $F = BIl$ opposes motion (Lenz's law). If the rod is given initial velocity $v_0$ and released: it decelerates exponentially $v = v_0 e^{-B^2l^2t/(mR)}$ with time constant $\tau = mR/(B^2l^2)$. If pulled with constant velocity: the applied force equals the braking force. If pulled with constant force $F_0$: terminal velocity $v_t = F_0R/(B^2l^2)$.