Part of PC-08 — Chemical Kinetics

Quick Revision Snapshot

by Notetube Official224 words4 views

Essential Formulas at a Glance

Rate Law: rate=k[A]m[B]n;overall order=m+n\text{rate} = k[A]^m[B]^n; \quad \text{overall order} = m + n

Integrated Equations: [A]=[A]0kt(zero)[A] = [A]_0 - kt \quad \text{(zero)} k=2.303tlog[A]0[A](first)k = \frac{2.303}{t}\log\frac{[A]_0}{[A]} \quad \text{(first)} 1[A]=1[A]0+kt(second)\frac{1}{[A]} = \frac{1}{[A]_0} + kt \quad \text{(second)}

Half-Lives: t1/2(0)=[A]02k,t1/2(1)=0.693k,t1/2(2)=1k[A]0t_{1/2}^{(0)} = \frac{[A]_0}{2k}, \quad t_{1/2}^{(1)} = \frac{0.693}{k}, \quad t_{1/2}^{(2)} = \frac{1}{k[A]_0}

Units of k: (mol/L)1ns1(\text{mol/L})^{1-n} \cdot \text{s}^{-1}

Arrhenius: logk2k1=Ea2.303R(1T11T2)\log\frac{k_2}{k_1} = \frac{E_a}{2.303R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)

Ea relationship: Ea(fwd)Ea(bwd)=ΔHE_a(\text{fwd}) - E_a(\text{bwd}) = \Delta H

Key NEET Points (Must Know)

  1. First-order t_{1}/{2} is independent of [A]{0}
  2. Zero-order t_{1}/{2} is proportional to [A]{0}
  3. Catalyst lowers Ea but does NOT change ΔH\Delta H or K
  4. Order can be 0 or fractional; molecularity cannot
  5. Units of k: zero = mol/L/s; first = s1s^{-1}; second = L/mol/s
  6. Temperature in Arrhenius must be in Kelvin
  7. Slope of ln k vs 1/T = −Ea/R (negative)
  8. Pseudo first-order: one reactant in large excess

First-Order Completion Times (t_{1}/_{2} = t)

% Completion% RemainingHalf-lives (n)Time
50%50%1t
75%25%22t
87.5%12.5%33t
93.75%6.25%44t
99%1%6.646.64t
99.9%0.1%~10~10t

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes