Part of CALC-06 — Area Under Curves

Quick Area Formulas for JEE

by Notetube Official123 words7 views

Must-know area formulas: (1) Between y = xnx^n and y = x^1n\frac{1}{n} from 0 to 1: A = |1n+1\frac{1}{n+1} - nn+1\frac{n}{n+1}| = n1(n+1)\frac{n-1}{(n+1)} for n > 1, which simplifies differently; specifically for y = x2x^2 and y = sqrt(x), A = 1/3. (2) Between y2y^2 = 4ax and x2x^2 = 4by: A = 16ab/3. (3) Triangle with vertices (x1,y1), (x2,y2), (x3,y3): A = 12\frac{1}{2}|x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|. (4) Area cut off from parabola y2y^2 = 4ax by the line lx + my + n = 0: if the line intersects at points with parameters t1, t2, then A = 2a3\frac{2a}{3}|t1 - t2|^3 * a. (5) Between y = exe^x, x-axis, x = 0 to x = k: A = eke^k - 1.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes