For equations like $x^{2-5}$|x|+6=0 or |x|^2+3|x|-10=0: note that $x^2$=|x|^2. Substitute t=|x| (t>=0). Solve the quadratic in t. Discard negative t values. Each positive t gives two solutions: x=t and x=-t. t=0 gives one solution x=0. Total solutions = 2*(number of positive t roots) + (1 if t=0 is a root).