Standard form: y = xtan(theta) - gx^2/(2u^2*cos^2(theta))

Alternative form using Range: y = xtan(theta)(1 - x/R) where R = u^2sin(2*theta)/g

This form is elegant because:

• At x = 0: y = 0 (launch point) ✓
• At x = R: y = 0 (landing point) ✓
• At x = R/2: y = (R/4)*tan(theta) = H (maximum height) ✓

Radius of curvature at highest point: At the top, v = ucos(theta), centripetal acceleration = g r_top = v^2/g = u^2cos^2(theta)/g

Radius of curvature at launch: r_launch = u^2/(gcos(theta)) [velocity is u, component of g perpendicular to v is gcos(theta)]