Part of CG-04 — Ellipse

Position of a Point

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For x2x^2/a2a^2 + y2y^2/b2b^2 = 1, compute S1 = x12x1^2/a2a^2 + y12y1^2/b2b^2 - 1. S1 < 0: inside, S1 = 0: on the ellipse, S1 > 0: outside. The centre (0,0) gives S1 = -1 (inside). Any point (x1,y1) satisfying the inequality x12x1^2/a2a^2 + y12y1^2/b2b^2 < 1 is inside.

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