- **Tags**: optical-path, phase, path-difference
- **Difficulty**: Moderate
Optical path = geometrical path × refractive index = μt. Phase difference φ = 2π × (path difference)/λ = 2π$\Delta x$/λ. For a source with initial phase difference δ: total phase difference = 2π$\Delta x$/λ + δ. Converting between representations: path difference $\Delta x$ = nλ gives φ = 2nπ (constructive); $\Delta x$ = (n+1/2)λ gives φ = (2n+1)π (destructive). The relationship between intensity and phase: I = $I_{1}$ + $I_{2}$ + 2√($I_{1}$$I_{2}$)cosφ. For finding intensity at a specific point, first calculate the path difference from geometry, convert to phase difference, then substitute into the intensity formula. This systematic approach prevents sign errors common in JEE problems.$
Part of JOP-02 — Wave Optics: YDSE, Diffraction & Polarization
Optical Path and Phase Difference Relations
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