Part of JME-02 — Newton's Laws of Motion & Friction

Monkey and Rope Problem

by Notetube Official98 words4 views

Setup: A monkey of mass m climbs a rope hanging from the ceiling.

Case 1: Monkey climbs with constant velocity v: T = mg (no net force needed)

Case 2: Monkey accelerates upward at a: T - mg = ma => T = m(g + a)

Case 3: Monkey decelerates while climbing (a downward): T = m(g - a)

Case 4: Rope breaks at tension TmaxT_{max}: Maximum upward acceleration: amaxa_{max} = Tmaxm\frac{T_max}{m} - g

Two monkeys on a rope over a pulley: Treat like Atwood machine if masses differ. If the lighter monkey climbs, analyze using relative acceleration.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes