Part of JMAG-04 — Electromagnetic Waves & Spectrum

Maxwell's Displacement Current

by Notetube Official144 words3 views
  • Tags: displacement-current, Ampere, capacitor
  • Difficulty: Moderate

Ampere's circuital law (original): line integral of B.dl = mu0mu_0IenclosedI_{enclosed} works for steady currents but fails for time-varying fields. Consider a charging capacitor: a wire carries current I to the plates, but between the plates there is no conduction current. Yet the magnetic field must be continuous. Maxwell's resolution: a changing electric field between the plates acts as a "displacement current" IdI_d = epsilon0epsilon_0 * dPhiEdt\frac{Phi_E}{dt}. Between parallel plates: E = Qepsilon0A\frac{Q}{epsilon_0*A} = sigmaepsilon0\frac{sigma}{epsilon_0}, so PhiEPhi_E = EA = Qepsilon0\frac{Q}{epsilon_0}. Thus IdI_d = epsilon0epsilon_0 * dQ/epsilon0dt\frac{Q/epsilon_0}{dt} = dQdt\frac{dQ}{dt} = IcI_c (the conduction current in the wire). The modified Ampere-Maxwell law: line integral of B.dl = mu0mu_0*(IcI_c + IdI_d). Displacement current exists wherever the electric field changes with time, even in empty space. It is not a real flow of charges but produces the same magnetic effects.

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