Part of JTHERM-01 — Thermodynamics: Laws, Processes & Engines

Isothermal Process

by Notetube Official95 words4 views
  • id: JTHERM-01-N06
  • title: Isothermal Process — Constant Temperature
  • tags: isothermal, constant-T, boyle

Condition: temperature constant, ΔT=0\Delta T = 0, so ΔU=0\Delta U = 0. First Law: Q=WQ = W. The equation PV = nRT = constant gives Boyle's law: P1V1=P2V2P_1V_1 = P_2V_2. Work: W=nRTln(V2/V1)W = nRT\ln(V_2/V_1). On P-V diagram: rectangular hyperbola. Isothermal requires slow process (quasi-static) and thermal contact with a reservoir. The system absorbs heat from the reservoir to maintain constant T during expansion. For an isothermal process, specific heat is effectively infinite: CT=Q/(nΔT)=Q/0C_T = Q/(n\Delta T) = Q/0 \to \infty.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes