Part of ME-03 — Laws of Motion & Friction

Formula Sheet — Laws of Motion & Friction

by Notetube Official186 words11 views

Newton's Laws & Momentum

Fnet=ma[M1L1T2](N)\vec{F}_{net} = m\vec{a} \quad [M^1L^1T^{-2}] \quad \text{(N)}

Fnet=dpdtwherep=mv[M1L1T1](kg m/s)\vec{F}_{net} = \frac{d\vec{p}}{dt} \quad \text{where} \quad \vec{p} = m\vec{v} \quad [M^1L^1T^{-1}] \quad \text{(kg m/s)}

J=FΔt=Δp[M1L1T1](N⋅s)\vec{J} = \vec{F}\,\Delta t = \Delta\vec{p} \quad [M^1L^1T^{-1}] \quad \text{(N·s)}

m1u1+m2u2=m1v1+m2v2(conservation of momentum, Fext=0)m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2 \quad \text{(conservation of momentum, } F_{ext}=0\text{)}

Apparent Weight in Lift

Wup=m(g+a)[M1L1T2](N)W'_{up} = m(g + a) \quad [M^1L^1T^{-2}] \quad \text{(N)}

Wdown=m(ga)[M1L1T2](N)W'_{down} = m(g - a) \quad [M^1L^1T^{-2}] \quad \text{(N)}

Wfreefall=0(a=g)W'_{freefall} = 0 \quad (a = g)

Atwood Machine

a=(m1m2)gm1+m2[M0L1T2](m/s2)a = \frac{(m_1 - m_2)\,g}{m_1 + m_2} \quad [M^0L^1T^{-2}] \quad \text{(m/s}^2\text{)}

T=2m1m2gm1+m2[M1L1T2](N);m2g<T<m1gT = \frac{2m_1 m_2\,g}{m_1 + m_2} \quad [M^1L^1T^{-2}] \quad \text{(N)} \quad ; \quad m_2 g < T < m_1 g

Friction

fsμsN;fk=μkN;fr=μrN[dimensionless×M1L1T2]f_s \leq \mu_s N \quad ; \quad f_k = \mu_k N \quad ; \quad f_r = \mu_r N \quad [\text{dimensionless} \times M^1L^1T^{-2}]

tanθrepose=μs(angle of repose, dimensionless)\tan\theta_{repose} = \mu_s \quad \text{(angle of repose, dimensionless)}

Circular Motion

Fc=mv2r[M1L1T2](N)F_c = \frac{mv^2}{r} \quad [M^1L^1T^{-2}] \quad \text{(N)}

vmax,level=μrg[M0L1T1](m/s)v_{max,\,level} = \sqrt{\mu r g} \quad [M^0L^1T^{-1}] \quad \text{(m/s)}

tanθbank=v2rg(no friction, dimensionless)\tan\theta_{bank} = \frac{v^2}{rg} \quad \text{(no friction, dimensionless)}

Inclined Plane Components

N=mgcosθ;F=mgsinθ[M1L1T2]N = mg\cos\theta \quad ; \quad F_{\parallel} = mg\sin\theta \quad [M^1L^1T^{-2}]

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes