The hybridization of Xe in $XeF_{2}$ is __________ and its shape is __________. Answer: $sp^{3}$d; linear

The bond order of $F_{2}$ is __________ and it is __________ (para/dia)magnetic. Answer: 1; diamagnetic

The bond angle in $H_{2}O$ is __________ because it has __________ lone pairs on O. Answer: 104.5°; 2

For species with Z __________ 7, the MO filling order has π2p __________ σ2p. Answer: ≤ (less than or equal to); before (lower in energy than)

A molecule has SN = 6 with 2 lone pairs. Its hybridization is __________, electron geometry is __________, and molecular shape is __________. Answer: sp^{3}$$d^{2}; octahedral; square planar

The dipole moment of $CCl_{4}$ is __________ D because its __________ symmetry causes bond dipoles to __________. Answer: 0; tetrahedral; cancel

$O_{2}$ is __________ because MOT places __________ unpaired electrons in __________ orbitals. Answer: paramagnetic; 2; degenerate π*2p

In Fajan's rules, covalent character INCREASES with __________ cation size and __________ anion size. Answer: decreasing (smaller); increasing (larger)

The Born-Haber cycle equation is: U = $\Delta Hf$ − $\Delta Hs$ub − __________ − __________ − EA Answer: IE; ½$\Delta H$_diss

The bond order of $N_{2}$ is __________ and it is formed by __________ sigma and __________ pi bonds. Answer: 3; 1; 2

$XeF_{4}$ has __________ lone pairs on Xe, making it __________ shaped, unlike $SF_{6}$ which is __________. Answer: 2; square planar; octahedral

The resonance energy of benzene is approximately __________ kJ/mol, which explains its __________ stability. Answer: 150; extra (aromatic)

In $PCl_{5}$, axial P–Cl bonds are __________ than equatorial P–Cl bonds due to __________ repulsion. Answer: longer; greater (more 90° lp/bp repulsion from equatorial bonds)

CO is isoelectronic with __________ and has bond order __________. Answer: $N_{2}$; 3

The shape of $ClF_{3}$ is __________ with hybridization __________ because Cl has __________ lone pairs. Answer: T-shaped; $sp^{3}$d; 2