Part of EXP-01 — Experimental Skills & Laboratory Physics

Feynman Note | Understanding Why v = 2f(l₂ − l₁) Works

by Notetube Official251 words4 views

type: feynman_note | topic: resonance-tube-deeper-understanding

The Big Idea

Why do we need two resonance positions, not just one?

Imagine you are a sound wave traveling inside a tube. You know you form a "standing wave" — a pattern of nodes (stillness) and antinodes (maximum vibration). At resonance, the open end should be an antinode.

But there is a problem: the open end is not a perfect antinode at the exact rim of the tube. The air just outside the tube also vibrates a little. The effective resonance length is always slightly longer than the physical length of the air column by an amount e (the end correction).

First resonance: Physical length l_{1}. Effective length = l_{1} + e = λ/4. Second resonance: Physical length l_{2}. Effective length = l_{2} + e = 3λ/4.

Now here is the clever part. Both l_{1} and l_{2} are "infected" by the same end correction e. When we subtract:

l2l1=(3λ/4+e)(λ/4+e)=3λ4λ4=λ2l_2 - l_1 = (3\lambda/4 + e) - (\lambda/4 + e) = \frac{3\lambda}{4} - \frac{\lambda}{4} = \frac{\lambda}{2}

e disappears! We get a pure, end-correction-free measurement of half the wavelength. Then: v = fλ = 2f(l_{2} − l_{1}).

This is the beauty of taking the difference — it cancels a systematic error that would otherwise corrupt your measurement. This technique of "differencing to cancel systematics" is a cornerstone of experimental physics.

Takeaway

Never use only l_{1}. Always use BOTH resonances. The two-resonance method is intrinsically more accurate because it is self-correcting against the end correction.

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