Part of PH-01 — Dual Nature of Radiation & Matter

Exam Cheat Sheet

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PH-01 NEET Exam Cheat Sheet

CORE EQUATIONS

EquationFormulaNotes
Einstein's equationKE_max = hν − φIn J or eV; use same units
Stopping potentialeV0V_{0} = hν − φ → V0V_{0} = KE_max/eV0V_{0} in volts = KE_max in eV
Photon energy (fast)E = 1240/λ(nm) eVhc = 1240 eV·nm (memorize!)
Threshold wavelengthλ_{0} = 1240/φ(eV) nmDerived from hc/φ
de Broglie (general)λ = h/p = h/(mv)p in kg·m/s
Electron through Vλ = 1.227/√V nmONLY for electrons!
From KEλ = h/√(2m·KE)Any particle
Mass ratio at same Vλ_{1}/λ_{2} = √(m_{2}/m_{1})Same charge assumed

KEY FACTS (answer triggers)

  • V0V_{0} vs intensity → UNCHANGED (V0V_{0} = hν − φ/e, no intensity term)
  • KE_max vs intensity → UNCHANGED
  • Photocurrent vs intensity → INCREASES (∝ intensity)
  • Slope of KE vs ν → h (same for ALL metals)
  • Slope of V0V_{0} vs ν → h/e (same for ALL metals)
  • Davisson-Germer: 54 V, 50°, Ni crystal, 1927
  • λ_e/λ_p at same V → √(mp/me) ≈ 43
  • λ_e/λ_α at same V → ≈ 121

UNIT CHECKS

[h] = \text{J·s} = \text{kg·m}^2\text{·s}^{-1} = [ML^2$T^{-1}$] [\phi] = \text{J or eV} = [ML^2$T^{-2}$] [V_0] = \text{V} = \text{J/C} = [ML^2$T^{-3}A^{-1}$] [\lambda] = \text{m} = [L]$$

DECISION TREE FOR NUMERICALS

Given λ? → E = 1240/λ(nm) eV → KE_max = E − φ → $V_{0}$ = KE_max (in V)
Given ν? → E = hν → KE_max = hν − φ → $V_{0}$ = KE_max/e
Given V (accelerating) for electron? → λ = 1.227/√V nm
Given V for other particle? → λ = h/√(2mqV) [use specific m and q]
Given two λ_{1}, λ_{2} and $V_{01}$, $V_{02}$? → Subtract equations to find h, then find φ

CONSTANTS TO MEMORISE

hem_em_phc
6.63×10346.63 \times 10^{-34} J·s1.6×10191.6 \times 10^{-19} C9.1×10319.1 \times 10^{-31} kg1.67×10271.67 \times 10^{-27} kg1240 eV·nm

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