Part of OC-07 — Carboxylic Acids

Error Analysis — NEET Traps Table

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#Common TrapWrong ThinkingCorrect Answer
1NaBH4 reduces carboxylic acids"NaBH4 reduces C=O, so it should reduce RCOOH"NaBH4 is too mild; RCOOH C=O is less electrophilic. Only LiAlH4 works.
2HCOOH is weaker than CH3COOH"More carbons = more organic = more acidic"HCOOH (pKa 3.75) > CH3COOH (4.76). H has no +I; CH3 has +I.
3Benzoic acid undergoes HVZ"All carboxylic acids undergo HVZ"No alpha-H → no HVZ. Benzoic acid alpha-C is sp2 aromatic ring.
4Formic acid undergoes HVZ"HCOOH has C–H, so it has alpha-H"The only C–H in HCOOH is the carboxyl C–H (C-1). No separate alpha-C exists.
5Soda lime decarboxylation of formate gives methane"HCOO– minus COOH should give H– = CH4""R" in formate = H, so product is H2 (not CH4).
6More alkyl groups = stronger acid"+I is electron withdrawal = stabilizes anion"+I (alkyl) is electron DONATION, destabilizing COO–, making acid weaker.
7Fischer esterification is irreversible"The acid is consumed"Fischer esterification is REVERSIBLE. Saponification is irreversible.
8Saponification gives free carboxylic acid"Ester + NaOH → acid + alcohol"Saponification gives carboxylate SALT (RCOONa), not free acid (RCOOH).
9Kolbe electrolysis occurs at cathode"Reduction = cathode = coupling"Kolbe is OXIDATIVE (at anode). RCOO– → RCOO• → R• + CO2 → R–R.
10PCl5 is preferred over SOCl2 for acyl chlorides"Both do the same job"SOCl2 gives gaseous byproducts (SO2, HCl); PCl5 gives liquid POCl3. SOCl2 is preferred.

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