| # | Common Trap | Wrong Thinking | Correct Answer |
|---|---|---|---|
| 1 | NaBH4 reduces carboxylic acids | "NaBH4 reduces C=O, so it should reduce RCOOH" | NaBH4 is too mild; RCOOH C=O is less electrophilic. Only LiAlH4 works. |
| 2 | HCOOH is weaker than CH3COOH | "More carbons = more organic = more acidic" | HCOOH (pKa 3.75) > CH3COOH (4.76). H has no +I; CH3 has +I. |
| 3 | Benzoic acid undergoes HVZ | "All carboxylic acids undergo HVZ" | No alpha-H → no HVZ. Benzoic acid alpha-C is sp2 aromatic ring. |
| 4 | Formic acid undergoes HVZ | "HCOOH has C–H, so it has alpha-H" | The only C–H in HCOOH is the carboxyl C–H (C-1). No separate alpha-C exists. |
| 5 | Soda lime decarboxylation of formate gives methane | "HCOO– minus COOH should give H– = CH4" | "R" in formate = H, so product is H2 (not CH4). |
| 6 | More alkyl groups = stronger acid | "+I is electron withdrawal = stabilizes anion" | +I (alkyl) is electron DONATION, destabilizing COO–, making acid weaker. |
| 7 | Fischer esterification is irreversible | "The acid is consumed" | Fischer esterification is REVERSIBLE. Saponification is irreversible. |
| 8 | Saponification gives free carboxylic acid | "Ester + NaOH → acid + alcohol" | Saponification gives carboxylate SALT (RCOONa), not free acid (RCOOH). |
| 9 | Kolbe electrolysis occurs at cathode | "Reduction = cathode = coupling" | Kolbe is OXIDATIVE (at anode). RCOO– → RCOO• → R• + CO2 → R–R. |
| 10 | PCl5 is preferred over SOCl2 for acyl chlorides | "Both do the same job" | SOCl2 gives gaseous byproducts (SO2, HCl); PCl5 gives liquid POCl3. SOCl2 is preferred. |
Part of OC-07 — Carboxylic Acids
Error Analysis — NEET Traps Table
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