Part of OC-06 — Aldehydes & Ketones

Error Analysis — Common Mistakes in OC-06 (8 Errors)

by Notetube Official337 words8 views

Error 1: Thinking Ketones Give Positive Tollens' Test

Wrong belief: "Acetone has a C=O group, so it will give a silver mirror." Correct fact: Tollens' oxidizes the aldehyde C-H bond; ketones have no such bond. Ketones do NOT give silver mirror. Trigger: When you see "C=O present → Tollens' positive" — WRONG. Must be an aldehyde.

Error 2: Confusing Clemmensen and Wolff-Kishner Products

Wrong belief: "Clemmensen gives alcohol, Wolff-Kishner gives hydrocarbon." Correct fact: BOTH give CH2 (complete deoxygenation). NaBH4/LiAlH4 gives alcohol (C-OH retained).

Error 3: Saying Benzaldehyde Undergoes Aldol Condensation

Wrong belief: "Benzaldehyde has an aldehyde group, so it gives aldol." Correct fact: Benzaldehyde has NO alpha-H (adjacent C is benzene ring carbon). It undergoes Cannizzaro, not aldol.

Error 4: Methanol Gives Positive Iodoform Test

Wrong belief: "Methanol is an alcohol, so it gives iodoform like ethanol." Correct fact: Methanol (CH3OH) is oxidized to HCHO (formaldehyde), which has no CH3CO- group. Iodoform test is NEGATIVE for methanol.

Error 5: 2,4-DNP Test Distinguishes Aldehydes from Ketones

Wrong belief: "2,4-DNP is positive for aldehydes, negative for ketones." Correct fact: 2,4-DNP is positive for ALL C=O-containing compounds (both aldehydes and ketones). It only detects C=O, not its type.

Error 6: Thinking NaBH4 Completely Removes Oxygen (Like Clemmensen)

Wrong belief: "NaBH4 and Clemmensen both remove the carbonyl oxygen." Correct fact: NaBH4 reduces C=O to C-OH (alcohol, oxygen retained). Clemmensen reduces C=O to CH2 (oxygen completely removed).

Error 7: Diethyl Ketone Gives Positive Iodoform

Wrong belief: "Diethyl ketone is a ketone and contains C=O, so it gives iodoform." Correct fact: Diethyl ketone (CH3CH2COCH2CH3) has NO CH3CO- group — both sides of C=O are ethyl. It does NOT give iodoform. Only methyl ketones (CH3CO-R) are iodoform-positive.

Error 8: Isopropanol Does Not Give Iodoform

Wrong belief: "Isopropanol is a secondary alcohol, not a methyl ketone. So no iodoform." Correct fact: Isopropanol (CH3CHOHCH3) is first oxidized to acetone (CH3COCH3) by I2/NaOH. Acetone is a methyl ketone → iodoform positive. The test can also oxidize secondary methyl carbinols.

Like these notes? Save your own copy and start studying with NoteTube's AI tools.

Sign up free to clone these notes