Part of JMAG-02 — Electromagnetic Induction & Lenz's Law

Energy Stored in an Inductor

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An inductor carrying current II stores energy U=12LI2U = \frac{1}{2}LI^2 in its magnetic field. This is analogous to U=12CV2U = \frac{1}{2}CV^2 for a capacitor. The energy is stored in the magnetic field itself, with energy density u=B2/(2μ0)u = B^2/(2\mu_0) (compare: electric field energy density uE=ε0E2/2u_E = \varepsilon_0 E^2/2). For a solenoid: U=12LI2=B22μ0×AlU = \frac{1}{2}LI^2 = \frac{B^2}{2\mu_0} \times Al (total energy = energy density ×\times volume). When the current is switched off, the stored energy must go somewhere — it can cause sparks across switches (back-EMF).

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