Part of JES-01 — Electrostatics: Coulomb's Law, Field & Gauss's Law

Electric Field Due to Continuous Charge Distributions

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For continuous distributions, replace the point charge sum with an integral: dE = kdq/r2r^2. Three types: (1) Linear lambdaCm\frac{lambda C}{m}: dq = lambdadl; (2) Surface (sigma C/m2m^2): dq = sigmadA; (3) Volume (rho C/m3m^3): dq = rhodV. Important results derived by integration: Ring on axis at distance x: E = kQxx2+R2\frac{kQx}{x^2 + R^2}^32\frac{3}{2} along axis. Maximum field of ring at x = Rsqrt\frac{R}{sqrt}(2). Infinite line charge: E = lambda2piepsilon0r\frac{lambda}{2*pi*epsilon_0*r} radially. Infinite plane: E = sigma2epsilon0\frac{sigma}{2*epsilon_0} perpendicular to surface. Strategy: identify symmetry to determine which component survives, then integrate only that component.

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