MO Diagram for (Z ≤ 7, with s-p mixing)
The MO energy order for homonuclear diatomics with Z ≤ 7:
electron configuration (14e):
- Bonding electrons: σ1s(2) + σ2s(2) + π2p(4) + σ2p(2) = 10
- Antibonding electrons: σ1s(2) + σ2s(2) = 4
- BO = (10−4)/2 = 3; Diamagnetic
MO Diagram for (Z > 7, no mixing)
electron configuration (16e):
- Bonding: 10; Antibonding: 6; BO = (10−6)/2 = 2; Paramagnetic (2 unpaired in π*2p)
Bond Order Summary Table
| Species | Total | Nb | Na | BO | Magnetic |
|---|---|---|---|---|---|
| 2 | 2 | 0 | 1 | Diamagnetic | |
| 3 | 2 | 1 | 0.5 | Paramagnetic | |
| 4 | 2 | 2 | 0 | Doesn't exist | |
| 6 | 4 | 2 | 1 | Diamagnetic | |
| 8 | 4 | 4 | 0 | Doesn't exist | |
| 10 | 6 | 4 | 1 | Paramagnetic | |
| 12 | 8 | 4 | 2 | Diamagnetic | |
| 14 | 10 | 4 | 3 | Diamagnetic | |
| 16 | 10 | 6 | 2 | Paramagnetic | |
| 18 | 10 | 8 | 1 | Diamagnetic | |
| 20 | 10 | 10 | 0 | Doesn't exist |
Visual Reference
Molecular Orbital Diagram — $N_{2}$Energy →
N atom MOs () N atom
1s 2s 2p 1s 2s 2p ↑↓ σ1s (2$e^{-}$) ↑↓ σ*1s (2$e^{-}$) ↑↓ σ2s (2$e^{-}$) ↑↓ σ*2s (2$e^{-}$) ↑↓ π2p ↑↓ π2p (4$e^{-}$) ↑↓ σ2p (2$e^{-}$) π*2p (0$e^{-}$) σ*2p (0$e^{-}$) $N_{2}$ (Z≤7): π2p fills BEFORE σ2pBond Order = (Nb − Na)/2 = (10 − 4)/2 = 3 (triple bond)
Source: Wikimedia Commons — Dinitrogen MO diagram ()